3.42 \(\int \sqrt {-1+\cot ^2(x)} \, dx\)

Optimal. Leaf size=42 \[ \sqrt {2} \tanh ^{-1}\left (\frac {\sqrt {2} \cot (x)}{\sqrt {\cot ^2(x)-1}}\right )-\tanh ^{-1}\left (\frac {\cot (x)}{\sqrt {\cot ^2(x)-1}}\right ) \]

[Out]

-arctanh(cot(x)/(-1+cot(x)^2)^(1/2))+arctanh(cot(x)*2^(1/2)/(-1+cot(x)^2)^(1/2))*2^(1/2)

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Rubi [A]  time = 0.03, antiderivative size = 42, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 5, integrand size = 10, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.500, Rules used = {3661, 402, 217, 206, 377} \[ \sqrt {2} \tanh ^{-1}\left (\frac {\sqrt {2} \cot (x)}{\sqrt {\cot ^2(x)-1}}\right )-\tanh ^{-1}\left (\frac {\cot (x)}{\sqrt {\cot ^2(x)-1}}\right ) \]

Antiderivative was successfully verified.

[In]

Int[Sqrt[-1 + Cot[x]^2],x]

[Out]

-ArcTanh[Cot[x]/Sqrt[-1 + Cot[x]^2]] + Sqrt[2]*ArcTanh[(Sqrt[2]*Cot[x])/Sqrt[-1 + Cot[x]^2]]

Rule 206

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1*ArcTanh[(Rt[-b, 2]*x)/Rt[a, 2]])/(Rt[a, 2]*Rt[-b, 2]), x]
 /; FreeQ[{a, b}, x] && NegQ[a/b] && (GtQ[a, 0] || LtQ[b, 0])

Rule 217

Int[1/Sqrt[(a_) + (b_.)*(x_)^2], x_Symbol] :> Subst[Int[1/(1 - b*x^2), x], x, x/Sqrt[a + b*x^2]] /; FreeQ[{a,
b}, x] &&  !GtQ[a, 0]

Rule 377

Int[((a_) + (b_.)*(x_)^(n_))^(p_)/((c_) + (d_.)*(x_)^(n_)), x_Symbol] :> Subst[Int[1/(c - (b*c - a*d)*x^n), x]
, x, x/(a + b*x^n)^(1/n)] /; FreeQ[{a, b, c, d}, x] && NeQ[b*c - a*d, 0] && EqQ[n*p + 1, 0] && IntegerQ[n]

Rule 402

Int[((a_) + (b_.)*(x_)^2)^(p_.)/((c_) + (d_.)*(x_)^2), x_Symbol] :> Dist[b/d, Int[(a + b*x^2)^(p - 1), x], x]
- Dist[(b*c - a*d)/d, Int[(a + b*x^2)^(p - 1)/(c + d*x^2), x], x] /; FreeQ[{a, b, c, d}, x] && NeQ[b*c - a*d,
0] && GtQ[p, 0] && (EqQ[p, 1/2] || EqQ[Denominator[p], 4])

Rule 3661

Int[((a_) + (b_.)*((c_.)*tan[(e_.) + (f_.)*(x_)])^(n_))^(p_), x_Symbol] :> With[{ff = FreeFactors[Tan[e + f*x]
, x]}, Dist[(c*ff)/f, Subst[Int[(a + b*(ff*x)^n)^p/(c^2 + ff^2*x^2), x], x, (c*Tan[e + f*x])/ff], x]] /; FreeQ
[{a, b, c, e, f, n, p}, x] && (IntegersQ[n, p] || IGtQ[p, 0] || EqQ[n^2, 4] || EqQ[n^2, 16])

Rubi steps

\begin {align*} \int \sqrt {-1+\cot ^2(x)} \, dx &=-\operatorname {Subst}\left (\int \frac {\sqrt {-1+x^2}}{1+x^2} \, dx,x,\cot (x)\right )\\ &=2 \operatorname {Subst}\left (\int \frac {1}{\sqrt {-1+x^2} \left (1+x^2\right )} \, dx,x,\cot (x)\right )-\operatorname {Subst}\left (\int \frac {1}{\sqrt {-1+x^2}} \, dx,x,\cot (x)\right )\\ &=2 \operatorname {Subst}\left (\int \frac {1}{1-2 x^2} \, dx,x,\frac {\cot (x)}{\sqrt {-1+\cot ^2(x)}}\right )-\operatorname {Subst}\left (\int \frac {1}{1-x^2} \, dx,x,\frac {\cot (x)}{\sqrt {-1+\cot ^2(x)}}\right )\\ &=-\tanh ^{-1}\left (\frac {\cot (x)}{\sqrt {-1+\cot ^2(x)}}\right )+\sqrt {2} \tanh ^{-1}\left (\frac {\sqrt {2} \cot (x)}{\sqrt {-1+\cot ^2(x)}}\right )\\ \end {align*}

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Mathematica [A]  time = 0.04, size = 60, normalized size = 1.43 \[ \frac {\sin (x) \sqrt {\cot ^2(x)-1} \left (\sqrt {2} \log \left (\sqrt {2} \cos (x)+\sqrt {\cos (2 x)}\right )-\tanh ^{-1}\left (\frac {\cos (x)}{\sqrt {\cos (2 x)}}\right )\right )}{\sqrt {\cos (2 x)}} \]

Antiderivative was successfully verified.

[In]

Integrate[Sqrt[-1 + Cot[x]^2],x]

[Out]

(Sqrt[-1 + Cot[x]^2]*(-ArcTanh[Cos[x]/Sqrt[Cos[2*x]]] + Sqrt[2]*Log[Sqrt[2]*Cos[x] + Sqrt[Cos[2*x]]])*Sin[x])/
Sqrt[Cos[2*x]]

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fricas [B]  time = 1.56, size = 123, normalized size = 2.93 \[ \frac {1}{2} \, \sqrt {2} \log \left (-2 \, \sqrt {-\frac {\cos \left (2 \, x\right )}{\cos \left (2 \, x\right ) - 1}} \sin \left (2 \, x\right ) - 2 \, \cos \left (2 \, x\right ) - 1\right ) - \frac {1}{2} \, \log \left (\frac {\sqrt {2} \sqrt {-\frac {\cos \left (2 \, x\right )}{\cos \left (2 \, x\right ) - 1}} \sin \left (2 \, x\right ) + \cos \left (2 \, x\right ) + 1}{\cos \left (2 \, x\right ) + 1}\right ) + \frac {1}{2} \, \log \left (\frac {\sqrt {2} \sqrt {-\frac {\cos \left (2 \, x\right )}{\cos \left (2 \, x\right ) - 1}} \sin \left (2 \, x\right ) - \cos \left (2 \, x\right ) - 1}{\cos \left (2 \, x\right ) + 1}\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((-1+cot(x)^2)^(1/2),x, algorithm="fricas")

[Out]

1/2*sqrt(2)*log(-2*sqrt(-cos(2*x)/(cos(2*x) - 1))*sin(2*x) - 2*cos(2*x) - 1) - 1/2*log((sqrt(2)*sqrt(-cos(2*x)
/(cos(2*x) - 1))*sin(2*x) + cos(2*x) + 1)/(cos(2*x) + 1)) + 1/2*log((sqrt(2)*sqrt(-cos(2*x)/(cos(2*x) - 1))*si
n(2*x) - cos(2*x) - 1)/(cos(2*x) + 1))

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giac [F(-1)]  time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((-1+cot(x)^2)^(1/2),x, algorithm="giac")

[Out]

Timed out

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maple [A]  time = 0.23, size = 35, normalized size = 0.83 \[ -\ln \left (\cot \relax (x )+\sqrt {-1+\cot ^{2}\relax (x )}\right )+\arctanh \left (\frac {\cot \relax (x ) \sqrt {2}}{\sqrt {-1+\cot ^{2}\relax (x )}}\right ) \sqrt {2} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((-1+cot(x)^2)^(1/2),x)

[Out]

-ln(cot(x)+(-1+cot(x)^2)^(1/2))+arctanh(cot(x)*2^(1/2)/(-1+cot(x)^2)^(1/2))*2^(1/2)

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maxima [F(-2)]  time = 0.00, size = 0, normalized size = 0.00 \[ \text {Exception raised: RuntimeError} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((-1+cot(x)^2)^(1/2),x, algorithm="maxima")

[Out]

Exception raised: RuntimeError >> ECL says: Error executing code in Maxima: sign: argument cannot be imaginary
; found %i

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mupad [B]  time = 0.43, size = 34, normalized size = 0.81 \[ \sqrt {2}\,\mathrm {atanh}\left (\frac {\sqrt {2}\,\mathrm {cot}\relax (x)}{\sqrt {{\mathrm {cot}\relax (x)}^2-1}}\right )-\ln \left (\mathrm {cot}\relax (x)+\sqrt {{\mathrm {cot}\relax (x)}^2-1}\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((cot(x)^2 - 1)^(1/2),x)

[Out]

2^(1/2)*atanh((2^(1/2)*cot(x))/(cot(x)^2 - 1)^(1/2)) - log(cot(x) + (cot(x)^2 - 1)^(1/2))

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sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \sqrt {\cot ^{2}{\relax (x )} - 1}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((-1+cot(x)**2)**(1/2),x)

[Out]

Integral(sqrt(cot(x)**2 - 1), x)

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